co-CDH ⇒ co-CDH without an isomorphism
Statement
Let output a bilinear group pair with an efficiently computable isomorphism for which co-CDH is hard, and let output the same pair with the generator of . Then co-CDH without an isomorphism is hard for , with the same advantage — folklore.
Sketch
The map sends a uniform co-CDH instance to a uniform instance with and , whose answer is .