SXDH (Symmetric External Diffie-Hellman) ⇒ BDH
SXDH (Symmetric External Diffie-Hellman) implies BDH.
Statement
Migrated verbatim from bilinear-map-assumptions:
Assumes DDH is hard in both and of an asymmetric pairing. Stronger than BDDH; used for efficiently instantiating Groth-Sahai proofs.
Notes
source: folklore: the claim carried no citation on the page it was
migrated from, and none was invented.
class: unstated: no citing page says which notion of reduction is meant.
Recording a class the wiki does not state would add a claim.
Recorded during migration and not fixed — these are claims about the source text, not changes to it:
- Stronger than BDDH is the only statement of direction; no citation.
- SUSPECTED IMPRECISION: SXDH is stated for asymmetric (Type 3) pairings whereas BDDH is stated on this page for symmetric pairings, so the two are not directly comparable.